Home Physics Electrostatics Potential & Capacitance JEE Main 2019 An electric field of 1000 V/m is applied to …
Physics Electrostatics Potential & Capacitance JEE Main 2019 MCQ (Single Correct)

An electric field of 1000 V/m is applied to an electric dipole at angle of 45°. The value of electric dipole moment is C.m. What is the potential energy of the electric dipole?

A
B
C
D

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The correct answer is:
B

JEE Main 2019

Potential energy of a dipole is given by

[where θ = angle between dipole and perpendicular to the field]

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